确定过时数据

awk 'BEGIN { count = 1} { if ( $2 == prev ) { ++count; if ( ! start ) {start = prevtime} end = $1 } 
       else if ( count >= 10 ) { print start, end, prev; count = 1; start = "" }
       else { start = "" }; 
       prev = $2; prevtime = $1 }' file.dat

编辑2:

发现并修复了另一个错误。

这是我的版本,更详细:

# This function prints out the summary only when count >= 10
function print_summary(count, first, last, value) {
    if (count >= 10) {
        printf "%s through %s %s (%d)\n", first, last, last_value, count
    }
}

$2 == last_value {
    last_occurance = $1
    count++
}

$2 != last_value {
    print_summary(count, first_occurance, last_occurance, last_value)
    first_occurance = $1
    last_value = $2
    count = 1
}

END { 
    print_summary(count, first_occurance, last_occurance, last_value)
}