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在保持工作流时接收PersistenceException

workflow-foundation workflow

1

ksa · 技术社区 · 15 年前

以下是我在持久化工作流时获取的异常的堆栈跟踪:

System.Workflow.Runtime.Hosting.PersistenceException: Type 'System.Xml.XmlElement' in Assembly 'System.Xml, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' is not marked as serializable. ---> System.Runtime.Serialization.SerializationException: Type 'System.Xml.XmlElement' in Assembly 'System.Xml, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' is not marked as serializable.
   at System.Runtime.Serialization.FormatterServices.InternalGetSerializableMembers(RuntimeType type)
   at System.Runtime.Serialization.FormatterServices.GetSerializableMembers(Type type, StreamingContext context)
   at System.Runtime.Serialization.Formatters.Binary.WriteObjectInfo.InitMemberInfo()
   at System.Runtime.Serialization.Formatters.Binary.WriteObjectInfo.InitSerialize(Object obj, ISurrogateSelector surrogateSelector, StreamingContext context, SerObjectInfoInit serObjectInfoInit, IFormatterConverter converter, ObjectWriter objectWriter)
   at System.Runtime.Serialization.Formatters.Binary.WriteObjectInfo.Serialize(Object obj, ISurrogateSelector surrogateSelector, StreamingContext context, SerObjectInfoInit serObjectInfoInit, IFormatterConverter converter, ObjectWriter objectWriter)
   at System.Runtime.Serialization.Formatters.Binary.ObjectWriter.Serialize(Object graph, Header[] inHeaders, __BinaryWriter serWriter, Boolean fCheck)
   at System.Runtime.Serialization.Formatters.Binary.BinaryFormatter.Serialize(Stream serializationStream, Object graph, Header[] headers, Boolean fCheck)
   at System.Runtime.Serialization.Formatters.Binary.BinaryFormatter.Serialize(Stream serializationStream, Object graph)
   at System.Workflow.ComponentModel.Activity.Save(Stream stream, IFormatter formatter)
   at System.Workflow.ComponentModel.Activity.Save(Stream stream)
   at System.Workflow.Runtime.Hosting.WorkflowPersistenceService.GetDefaultSerializedForm(Activity activity)
   at System.Workflow.Runtime.Hosting.SqlWorkflowPersistenceService.SaveWorkflowInstanceState(Activity rootActivity, Boolean unlock)
   at System.Workflow.Runtime.WorkflowExecutor.Persist(Activity dynamicActivity, Boolean unlock, Boolean needsCompensation)
   --- End of inner exception stack trace ---
   at System.Workflow.Runtime.WorkflowExecutor.Persist(Activity dynamicActivity, Boolean unlock, Boolean needsCompensation)
   at System.Workflow.Runtime.WorkflowExecutor.ProtectedPersist(Boolean unlock)

如何在何处调试此异常?

1 回复 | 直到 13 年前

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Maurice 15 年前

错误消息在顶部显示:

程序集中的“system.xml.xmlElement” 'system.xml,版本=2.0.0.0, 文化=中性, publickeytoken=b7a5c561934e089'是未标记为可序列化。

当工作流被持久化时,WorkflowPersistenceService使用二进制序列化程序来转储工作流中的所有数据。因此,其中的所有内容必须要么标记为不可序列化,要么必须是二进制可序列化。xmlElement不是这样的,所以您必须以其他方式存储数据,或者根本不保存数据。