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在android中共享图像时出错

share image android java

3

Parekh · 技术社区 · 9 年前

在android中,我不能以jpeg和png格式共享图像。请帮助并更正我的代码

每当我编写共享代码时,它都会给出异常“文件格式不受支持”
这是我的代码:

Uri imageUri = Uri.parse("android.resource://com.parekh.shareimage/drawable");
    Intent shareIntent = new Intent();
    shareIntent.setAction(Intent.ACTION_SEND);
    shareIntent.putExtra(Intent.EXTRA_TEXT, "My sample image text");
    shareIntent.putExtra(Intent.EXTRA_STREAM, imageUri);
    shareIntent.setType("image/*");
    startActivity(shareIntent);

1 回复 | 直到 9 年前

1

2

Oleg Filimonov madhan kumar 9 年前

将您的可绘制图像存储到内部存储器中,然后选择该图像。这条路会帮助你。

try{

        Bitmap bm = BitmapFactory.decodeResource(getResources(), R.drawable.shareforma);
        String extStorageDirectory = Environment.getExternalStorageDirectory().toString();
        File file = new File(extStorageDirectory, "forma.PNG");
        FileOutputStream outStream = new FileOutputStream(file);
        bm.compress(Bitmap.CompressFormat.PNG, 100, outStream);
        outStream.flush();
        outStream.close();
    }
    catch (IOException e) {
        e.printStackTrace();
    }
    String msgText = "Sample Message";

    Intent shareIntent = new Intent(android.content.Intent.ACTION_SEND);
    shareIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
    shareIntent.setType("image/*");

    //set your message
    shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, msgText); 

    String imagePath = Environment.getExternalStorageDirectory() + File.separator + "image_name.jpg";

    File imageFileToShare = new File(imagePath);

    Uri uri = Uri.fromFile(imageFileToShare);

    shareIntent.putExtra(Intent.EXTRA_STREAM, uri);

    startActivity(Intent.createChooser(shareIntent, msgText));