在单词之间替换下划线(reg.exp)

这应该在javascript中工作:

var newString = oldString.replace(/([^_].*?)_(?=[^_|^\s])/g,"$1 ");

编辑:如果字符串中已经有空白,可能需要添加如下内容:

var newString = oldString.replace(/([^_|\s].*?)_(?=[^_|^s])/g,"$1 ");

我忘了其他的边缘保护套吗?:)哦,是的,另一个边缘案例。如果后面跟空格(如换行符、行尾等),请使用结束下划线。

编辑:如果单词之间的下划线数为1,则另一个解决方案

var arrayString = oldString.replace(/^(_+)(.*?)(_+)$/g,"$1;$2;$3");
var a = arrayString.split(";");
var newString = a[0]+a[1].replace(/_/g," ")+a[2];

我认为使用regex和字符串替换会更简单。这里有一个Python的答案,因为我对jQuery、Java或XSLT不够熟悉:

import re

def mangle_string(string):
    """
    Replace underscores between letters with spaces, leave leading and
    trailing underscores alone.
    """
    # Match a string that starts with zero or more underscores, followed by a
    # non-underscore, followed by zero or more of any characters, followed by
    # another non-underscore, followed by zero or more underscores, then the
    # end of the string.  If the string doesn't match that pattern, then return
    # it unmodified.
    m = re.search(r'^(_*)([^_]+.*[^_]+)(_*)$', string)
    if not m:
        return string
    # Return the concatentation of first group (the leading underscores), then
    # the middle group (everything else) with any internal underscores
    # replaced with spaces, then the last group (the trailing underscores).
    return m.group(1) + m.group(2).replace('_', ' ') + m.group(3)

也许这就是你想要的(javascript):

var newString = oldString.replace(/(\w)_(\w)/g, "$1 $2");

如果单词之间有多个下划线,则:

var newString = oldString.replace(/(\w)_+(\w)/g, "$1 $2");

如果要保留与下划线相同的空格数:

var newString = oldString.replace(/(\w)(_+)(\w)/g, function(_, l1, u, l2) {
  return l1 + (u.length == 1 ? ' ' : (new Array(u.length - 1).join(' '))) + l2;
});

我不会用瑞格来做这个。我将计算前导和尾随下划线,然后将前导子字符串(如果有)与 middle.replace('_',' ') 以及尾随子串(如果有)。如果前导下划线指向末尾,则立即返回原始字符串。