代码之家 › 专栏 › 技术社区 › Shriram Kadam

如何在目标c中以19.0176°N、72.8562°E的格式显示纬度和经度

latitude-longitude core-location iphone objective-c

Shriram Kadam · 技术社区 · 9 年前

我使用以下代码获取当前位置,我添加了Corelocation框架

- (void)viewDidLoad {
    [super viewDidLoad];

    locationManager = [[CLLocationManager alloc] init];
    locationManager.delegate = self;
    locationManager.distanceFilter = kCLDistanceFilterNone; // whenever we move
    locationManager.desiredAccuracy = kCLLocationAccuracyHundredMeters; // 100 m
    [locationManager startUpdatingLocation];

}



- (void)locationManager:(CLLocationManager *)manager
    didUpdateToLocation:(CLLocation *)newLocation
           fromLocation:(CLLocation *)oldLocation
{

     NSLog(@"didUpdateToLocation: %@", newLocation);

    CLLocation *currentLocation = newLocation;

    if (currentLocation != nil) {


        NSInteger degrees = newLocation.coordinate.latitude;

        double decimal = fabs(newLocation.coordinate.latitude - degrees);

        int minutes = decimal * 60;

        double seconds = decimal * 3600 - minutes * 60;

        NSString *lattitudeStr = [NSString stringWithFormat:@"%dÂ° %d' %1.4f\"",
                                  degrees, minutes, seconds];

        _latitudeLabel.text = lattitudeStr;

        degrees = newLocation.coordinate.longitude;

        decimal = fabs(newLocation.coordinate.longitude - degrees);

        minutes = decimal * 60;

        seconds = decimal * 3600 - minutes * 60;

        NSString *longitudeStr = [NSString stringWithFormat:@"%dÂ° %d' %1.4f\"",
                                  degrees, minutes, seconds];

        _longitudeLabel.text = longitudeStr;


    }

     // Stop Location Manager
    [locationManager stopUpdatingLocation];

    NSLog(@"Resolving the Address");
    [geocoder reverseGeocodeLocation:currentLocation completionHandler:^
     (NSArray *placemarks, NSError *error)

 {
        NSLog(@"Found placemarks: %@, error: %@", placemarks, error);

        if (error == nil && [placemarks count] > 0) 
{
            placemark = [placemarks lastObject];

            _addressLabel.text = [NSString stringWithFormat:@"%@\n%@ %@\n%@\n%@",
                                   placemark.thoroughfare,
                                  placemark.postalCode, placemark.locality,
                                  placemark.administrativeArea,
                                  placemark.country];
        } else {
            NSLog(@"%@", error.debugDescription);
        }
    } ];

}

我正在获取的值为,纬度:19°1 3.4129,经度:72°51 22.1918,所以我需要在目标c中以19.0176°N,72.8562°E的格式显示坐标。如何获取准确的纬度和经度。如果我犯了错误,或者我需要添加任何其他方法、函数、框架或示例代码。

2 回复 | 直到 9 年前

tuledev 9 年前

您已经拥有这些值,请参见注释 this is what you want

if (currentLocation != nil) {


        NSInteger degrees = newLocation.coordinate.latitude; //<--- this is what you want

        NSString *lattitudeStr = [NSString stringWithFormat:@"%fÂ° N",
                                  degrees];

        _latitudeLabel.text = lattitudeStr;

        degrees = newLocation.coordinate.longitude; //<--- this is what you want


        NSString *longitudeStr = [NSString stringWithFormat:@"%fÂ° E",
                                  degrees];

        _longitudeLabel.text = longitudeStr;


    }

serdaryillar 9 年前

  NSString *lat = [self convertCoordinateFromDegreeMinuteSecond:@"19Â° 1â 3.4129â" position:@"N"];
  NSString *lon = [self convertCoordinateFromDegreeMinuteSecond:@"72Â° 51â 22.1918â" position:@"E"];


  - ( NSString * )convertCoordinateFromDegreeMinuteSecond:( NSString * )string position:( NSString * )position; {
  NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:@"0123456789."] invertedSet];

  NSArray *arrayLat = [string componentsSeparatedByString:@" "];

  if ( arrayLat.count == 3 ) {
      NSString *degree = [[arrayLat[ 0 ] componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""];
      NSString *minute = [[arrayLat[ 1 ] componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""];
      NSString *second = [[arrayLat[ 2 ] componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""];

      int    sign       = degree.doubleValue < 0 ? -1 : 1;
      double coordinate = ( degree.doubleValue + ( sign * ( minute.doubleValue / 60. ) ) + ( sign * ( second.doubleValue / 3600. ) ) );

      NSString *str = [NSString stringWithFormat:@"%fÂ° %@", coordinate, position];
      return str;

  } else {
      return @"NaN";
  }
}