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SWIFT:在数组中添加随机名称很困难

swift4 swift3 xcode swift arrays

Neillbar · 技术社区 · 6 年前

我的应用程序非常简单,首先你输入所有球员的名字,所有这些名字都存储到一个数组中。第二步,最后一个屏幕弹出一个句子,单击按钮后,句子将变为数组的第二个元素,再次单击将变为第三个元素,以此类推。。我能做的最简单的方法是每次单击它时删除数组[0]。

但是在这个数组句子中,我已经包含了玩家的名字(你在开头键入的那些名字,但我从玩家名字数组中提取了一个随机元素。因此,随机语句工作正常,但它不是每次单击时都提取一个随机名称。它提取的第一个随机元素会粘住…请帮助

ps:当我打印(p1)时,它会改变,但在屏幕/应用程序上不会改变

import UIKit

var q = ["Hello " + p1,"wie is die beste ? Malcolm is !!!","Hoe Gaan Dit " + p1 + " en met jou ook " + p2,"Gaan Baie goed dankie " + p1,"Wat Maak jy " + p2,"Ek sit maar hierso " + p2,"We are getting somewhere " + p1,"blah blah blah hoe gaan daai song van eminem alweer " + p1,"EK vorder met apps maak elke dag hehe " + p2,""]

var p1 = ""
var p2 = ""
var random = [String]()

var pc1 = 0
var pc2 = 0

/////////////////////////

@IBAction func next(_ sender: Any) {
  //chosing a random player

  pc1 = Int(arc4random_uniform(UInt32(players.count)))
  pc2 = Int(arc4random_uniform(UInt32(players.count)))

  if pc1 == pc2{
     pc1 = Int(arc4random_uniform(UInt32(players.count)))
     pc2 = Int(arc4random_uniform(UInt32(players.count)))
  }

  p1 = players[pc1]
  p2 = players[pc2]

  if q[0] != "" {
    dis.text = q[0]
    q.remove(at: 0)
  } else {
    dis.text = ""
  }   
}

2 回复 | 直到 6 年前

J Arango 6 年前

问题在于连接。您正在创建一个字符串数组,其中包含串联,当从操作内部调用该数组时,不会使用该数组的串联。

最好的解决方案是在action方法的范围内创建引号数组,并在索引上递增,直到达到数组的总计数。

为此,您必须在方法的作用域之外创建一个变量,并在其上递增,直到达到与q的计数相同的数字。一旦达到相同的计数,就会将其重置为0,然后重新开始该过程。

示例:

var p1 = ""
var p2 = ""
var random = [String]()

var pc1 = 0
var pc2 = 0
var index = 0


/////////////////////////

@IBAction func next(_ sender: Any) {
   //chosing a random player

 pc1 = Int(arc4random_uniform(UInt32(players.count)))
 pc2 = Int(arc4random_uniform(UInt32(players.count)))

 if pc1 == pc2{
     pc1 = Int(arc4random_uniform(UInt32(players.count)))
     pc2 = Int(arc4random_uniform(UInt32(players.count)))
 }

 p1 = players[pc1]
 p2 = players[pc2]

 // Array of quotes is now inside the scope of the method.
 var q = ["Hello " + p1,"wie is die beste ? Malcolm is !!!","Hoe Gaan Dit " + p1 + " en met jou ook " + p2,"Gaan Baie goed dankie " + p1,"Wat Maak jy " + p2,"Ek sit maar hierso " + p2,"We are getting somewhere " + p1,"blah blah blah hoe gaan daai song van eminem alweer " + p1,"EK vorder met apps maak elke dag hehe " + p2,""]

    // Using the quote
    dis.text = q[index]

    // Incrementing index
    index += 1

    // Keeping track of the index's count
    // and reseting it back to 0
    if index == q.count {
        index = 0
    }
}

这将帮助您解决问题,前提是这是您在应用程序实现中需要的。

祝你好运,希望这有帮助。

Will Richardson 6 年前

中的文本 q 如果它是ViewController的属性,则仅设置一次。如果要根据用户名进行更新,则需要在选择玩家名称后创建:

import UIKit

var currentIndex = 0
var p1 = ""
var p2 = ""
var random = [String]()

var pc1 = 0
var pc2 = 0

/////////////////////////

@IBAction func next(_ sender: Any) {
  //chosing a random player

  pc1 = Int(arc4random_uniform(UInt32(players.count)))
  pc2 = Int(arc4random_uniform(UInt32(players.count)))

  if pc1 == pc2{
     pc1 = Int(arc4random_uniform(UInt32(players.count)))
     pc2 = Int(arc4random_uniform(UInt32(players.count)))
  }

  p1 = players[pc1]
  p2 = players[pc2]

  var q = ["Hello " + p1,"wie is die beste ? Malcolm is !!!","Hoe Gaan Dit " + p1 + " en met jou ook " + p2,"Gaan Baie goed dankie " + p1,"Wat Maak jy " + p2,"Ek sit maar hierso " + p2,"We are getting somewhere " + p1,"blah blah blah hoe gaan daai song van eminem alweer " + p1,"EK vorder met apps maak elke dag hehe " + p2,""]

  if q[0] != "" {
    dis.text = q[currentIndex]
    currentIndex += 1
  } else {
    dis.text = ""
  }   
}