创建最小烧瓶/请求文件上载程序[重复]

我试过你们给我们举的例子,我想我找到了解决办法。

经过一些挖掘,我发现你可以 stream requests requests 模块:

请求支持流式上载,这允许您发送大型流或文件,而无需将其读入内存。

您只需要提供一个要流式传输的文件,并以读取二进制模式打开它, rb .

app.py

from flask import Flask, request
app = Flask(__name__)


@app.route('/',  methods=['GET', 'POST', 'PUT'])
def hello_world():
    # 'bw' is write binary mode
    with open("BigBuckBunny_320x180_flask_upload.mp4", "bw") as f:
        chunk_size = 4096
        while True:
            chunk = request.stream.read(chunk_size)
            if len(chunk) == 0:
                return 'Done'

            f.write(chunk)


if __name__ == '__main__':
    app.run()

上传器

import requests

# Give proper path to your file, I used mine from flask app directory
with open('BigBuckBunny_320x180.mp4', 'rb') as f:
    requests.post('http://127.0.0.1:5000/', data=f)

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