统计与变量不同的列表/元组元素?

无需生成列表,只需:

len(MyVar) - MyVar.count(0)

获取所有非0元素的子列表的长度

MyVar = [0,0,0,0,1,0,0,0,0]
len([x for x in MyVar if x != 0])
>> 1

以下各项应起作用:

>>> MyVar = [0,0,0,0,1,0,0,0,0]
>>> sum(map(bool, MyVar))
1

它会将列表转换为布尔值列表 True 当元素为非零时。然后它将通过隐式考虑 具有值1和 False

>>> len(filter(lambda x: x != 0, MyVar))
1

sum 在不需要任何中间列表或不必要的算术运算的条件生成器表达式上:

>>> sum(1 for element in MyVar if element != 0)
1

或者正如@Jean-Fran§ois Fabre所指出的:

>>> sum(1 for element in MyVar if element)
1

如果 MyVar

尝试使用 filter() :

>>> my_var = [0, 0, 0, 0, 1, 0, 0, 0, 0]
>>> result = filter(lambda x: x > 0, my_var)
[1]
>>> print(len(result))
1

myVar = [0,0,0,0,1,0,0,0,0]
count = 0

for var in myVar:
    if var != 0:
        count += 1

具有 reduce 从functools:

from functools import reduce

reduce((lambda x, y: x + (y>0)), MyVar, 0)

f = sum([1 for x in MyVar if x!= 0])

sum(x != 0 for x in MyVar)