理论上你可以实现你自己的
javax.persistence.spi.PersistenceUnitInfo
变成一个
MyPunit
然后做一些类似的事情
import java.util.ServiceLoader;
import javax.persistence.spi.PersistenceProvider;
...
PersistenceProvider pp = ServiceLoader.load(PersistenceProvider.class).iterator().next();
MyPunit conf = new MyPunit();
Map properties = new HashMap();
EntityManagerFactory emf = pp.createContainerEntityManagerFactory(conf, properties);
然而,应该没有必要这样做。你应该创建自己的持久性。应用程序的xml。你为什么要避免它?
这是最小的持久性。所需的xml,无需列出所有类(使用示例方言):
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="package.root.to.scan" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<non-jta-data-source>java:comp/env/jdbc/ourdb</non-jta-data-source>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQL95Dialect"/>
</properties>
</persistence-unit>
</persistence>