将数组传递给函数(C)

我编写了一个函数来旋转数组, 我已经检查过了,当代码在一个块中时,它就可以工作了,即所有 是在main()下编码的,但是当我分割代码以便在不同的函数下进行旋转时,我无法使其工作(它会截断而不是旋转)。 我很确定这与数组指针有关。

抱歉,完全没有

请帮助:

#include<stdio.h>
void rotate(int *arr,int length);
int main()
 {
 // this code creates an array via input
 int length;
 int i;
 int num;
    printf("enter length of array\n");
    scanf("%d",&length);
 int arr[length];
 for (i=0;i<length;i++) {
    printf("enter number\n");
    scanf("%d",&num);
    arr[i]=num;
 }
     // just prints original
    for(i=0;i<length;i++){
    printf("original arr[%d]=%d\n",i,arr[i]);

    }


 //runs rotate function

 rotate(arr,length);

 return 0;
 }

//the rotate function inputs rotation amount and uses nested for loop to 
execute
void rotate(int *arr,int length)
{
int n;
 printf("by how many do you want to rotate array?");
    scanf("%d",&n);
    int i;
    int j;
    int temp;
    for (j=0;j<n;j++)
    {
            temp=arr[0];
        for (i=0;i<length-1;i++)
        {

            arr[i]=arr[i+1]; 

        }
    arr[length-1]=temp;
            printf("rotated arr[%d] = %d\n",i,arr[i]);
    }


    }

我的输出如下所示:

enter length of array
5
enter number
1
enter number
2
enter number
3
enter number
4
enter number
5
original arr[0]=1
original arr[1]=2
original arr[2]=3
original arr[3]=4
original arr[4]=5
by how many do you want to rotate array?
3
rotated arr[4] = 1
rotated arr[4] = 2
rotated arr[4] = 3

RUN FINISHED; exit value 0; real time: 9s; user: 0ms; system: 0ms