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在Adobe Livecycle ES4中从数据节点中选择distinct元素

livecycle adobe

napi15 · 技术社区 · 6 年前

我有这个原始方法

var firstLine = ""

    if( frmStock.txtPRSID.rawValue <> null or frmStock.txtPRSDesp.rawValue <> null )
then
    firstLine = Concat(frmStock.txtPRSID.formattedValue," ",frmStock.txtPRSDesp.formattedValue)
endif

var secondLine = ""

if( frmStock.frmSN.txtSN.rawValue <> null )
then
    var snData = ref(frmStock.frmSN.txtSN.dataNode.parent)
    var snSet = ref(snData.resolveNodes("$.MaterialSerialID[*]"))
    var temp = ""
    for i=0 upto snSet.length-1
    do
        var Content = ref(snSet.item(i).resolveNode("$"))
        if( Content <> null )
        then
            temp = Concat(temp,Content.value)
            if( i <> snSet.length - 1 )
            then
                temp = Concat(temp,"\u000a")
            endif
        endif
    endfor
    secondLine = temp
endif

if( secondLine == "" )
then
    secondLine = Concat(frmStock.txtType.formattedValue," ",frmStock.txtID.formattedValue)
endif

this.rawValue = Concat(firstLine,"\u000a",secondLine)

我试图从原始方法的这一部分中只选择唯一且不同的元素:

/*This returns stuff like P0001 , P3333, P0001 , P444, P3333 */

 var snData = ref(frmStock.frmSN.txtSN.dataNode.parent)
    var snSet = ref(snData.resolveNodes("$.MaterialSerialID[*]"))
    var temp = ""
    for i=0 upto snSet.length-1
    do
        var Content = ref(snSet.item(i).resolveNode("$"))
        if( Content <> null )
        then
            temp = Concat(temp,Content.value)
            if( i <> snSet.length - 1 )
            then
                temp = Concat(temp,"\u000a")
            endif
        endif
    endfor

所以我想实现一个简单的解决方案是使用twp嵌套循环,使用这个逻辑 here

// Pick all elements one by one
        for (int i = 0; i < list.lengh; i++)
        {
            // Check 
            int j;
            for (j = 0; j < i; j++)
            if (arr[i] == arr[j])
                skip

            // If not add it to list 
            if (i == j)
            add to list 
        }

所以我试着把逻辑应用到我的方法中

var snData = ref(frmStock.frmSN.txtSN.dataNode.parent)
    var snSet = ref(snData.resolveNodes("$.MaterialSerialID[*]"))
    var temp = ""
    for i=0 upto snSet.length-1
    do
        for j=0 upto i-1 

    do
        var tempI= ref(snSet.item(i).resolveNode("$"))
         var tempJ= ref(snSet.item(j).resolveNode("$"))
         if(tempI <> tempJ) 
             then 
             break
         if(i==j) then 
        var Content = ref(snSet.item(i).resolveNode("$"))
        if( Content <> null )
        then
            temp = Concat(temp,Content.value)
            if( i <> snSet.length - 1 )
            then
                temp = Concat(temp,"\u000a")
            endif
        endif
        endif
        endif
            endfor
    endfor

我没有遇到任何错误,但返回的列表是空的,有人能帮我吗?如何仅从返回distinct元素 frmStock ?

1 回复 | 直到 6 年前

napi15 6 年前

我最终发现

我添加了一个函数

   function uniq(a) {
        return a.sort().filter(function(item, pos, ary) {
            return !pos || item != ary[pos - 1];
        })
    }

然后将其应用于项的数据源

var data = snData.resolveNodes("$.MaterialSerialID[*]");
var uniqData =  uniq(data);