拆分/标记化/扫描知道引号的字符串

类似这样的东西适用于您的输入:

    String text = "There's \"a man\" that live next door "
        + "'in my neighborhood', \"and he gets me down...\"";

    Scanner sc = new Scanner(text);
    Pattern pattern = Pattern.compile(
        "\"[^\"]*\"" +
        "|'[^']*'" +
        "|[A-Za-z']+"
    );
    String token;
    while ((token = sc.findInLine(pattern)) != null) {
        System.out.println("[" + token + "]");
    }

上面的照片( as seen on ideone.com ):

[There's]
["a man"]
[that]
[live]
[next]
[door]
['in my neighborhood']
["and he gets me down..."]

它使用 Scanner.findInLine ,其中regex模式是:

"[^"]*"      # double quoted token
'[^']*'      # single quoted token
[A-Za-z']+   # everything else

毫无疑问,这并不总是100%有效;报价可以嵌套等情况将是棘手的。

工具书类

• regular-expressions.info/Character class

根据你的逻辑,你会怀疑撇号和单引号之间的区别,也就是说。 There's 和 in my neighborhood

如果你想要以上的东西,你就必须开发出某种配对逻辑。我在想正则表达式。或者两部分解析。