在Linux中,如何使用POSIX方法从文件中读取Unicode-16字符串?

我有一个包含unicode-16字符串的文件,我想把它读到Linux程序中。字符串是从Windows的内部wchar格式原始写入的。(Windows是否总是使用UTF-16?例如,在日语版本中)

我相信我可以使用原始读取和wcstombs转换来读取它们,但是我无法确定要使用的区域设置。在我最新的Ubuntu和MacOSX机器上运行“locale-a”,可以生成零个以utf-16命名的区域设置。

有更好的方法吗?

更新:正确的答案和下面的其他帮助我指出使用libiconv。这是我用来做转换的函数。我现在把它放在一个类中,这个类将转换成一行代码。

// Function for converting wchar_t* to char*. (Really: UTF-16LE --> UTF-8)
// It will allocate the space needed for dest. The caller is
// responsible for freeing the memory.
static int iwcstombs_alloc(char **dest, const wchar_t *src)
{
  iconv_t cd;
  const char from[] = "UTF-16LE";
  const char to[] = "UTF-8";

  cd = iconv_open(to, from);
  if (cd == (iconv_t)-1)
  {
    printf("iconv_open(\"%s\", \"%s\") failed: %s\n",
           to, from, strerror(errno));
    return(-1);
  }

  // How much space do we need?
  // Guess that we need the same amount of space as used by src.
  // TODO: There should be a while loop around this whole process
  //       that detects insufficient memory space and reallocates
  //       more space.
  int len = sizeof(wchar_t) * (wcslen(src) + 1);

  //printf("len = %d\n", len);

  // Allocate space
  int destLen = len * sizeof(char);
  *dest = (char *)malloc(destLen);
  if (*dest == NULL)
  {
    iconv_close(cd);
    return -1;
  }

  // Convert

  size_t inBufBytesLeft = len;
  char *inBuf = (char *)src;
  size_t outBufBytesLeft = destLen;
  char *outBuf = (char *)*dest;

  int rc = iconv(cd,
                 &inBuf,
                 &inBufBytesLeft,
                 &outBuf,
                 &outBufBytesLeft);
  if (rc == -1)
  {
    printf("iconv() failed: %s\n", strerror(errno));
    iconv_close(cd);
    free(*dest);
    *dest = NULL;
    return -1;
  }

  iconv_close(cd);

  return 0;
} // iwcstombs_alloc()