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使用LDAP对使用Spring安全性的Adam进行身份验证

adam spring-security authentication java

Mike Q · 技术社区 · 14 年前

我正在尝试使用Spring Security获取Java应用程序,与我安装的本地亚当实例进行对话。

我已经成功地安装了Adam并安装了如下…

本地主机上运行的实例:389
根是 O=Company
- 一个叫孩子的孩子 OU=Company Users (组织AlUnit)
  - 一个外婆叫 CN=Mike Q (用户)
  - uid = mike 和 password = welcome

然后我设置了SpringSecurity(版本3.0.3、SpringFramework3.0.4和SpringLDAP 1.3.0)。弹簧文件

  <security:ldap-server id="contextSource" url="ldap://localhost:389/o=Company"/>

  <security:authentication-manager>
    <security:ldap-authentication-provider user-dn-pattern="uid={0},ou=Company Users"/>
  </security:authentication-manager>

  <bean class="com.xxx.test.TestAuthentication" lazy-init="false"/>

和测试验证

public class TestAuthentication
{
    @Autowired
    private AuthenticationManager authenticationManager;

    public void initialise()
    {
        Authentication authentication = new UsernamePasswordAuthenticationToken( "mike", "welcome" );
        Authentication reponseAuthentication = authenticationManager.authenticate( authentication );
    }
}

运行此程序时,出现以下错误

Caused by: javax.naming.AuthenticationException: [LDAP: error code 49 - 8009030C: LdapErr: DSID-0C090336, comment: AcceptSecurityContext error, data 2030, vece]
at com.sun.jndi.ldap.LdapCtx.mapErrorCode(LdapCtx.java:3041)
at com.sun.jndi.ldap.LdapCtx.processReturnCode(LdapCtx.java:2987)
at com.sun.jndi.ldap.LdapCtx.processReturnCode(LdapCtx.java:2789)
at com.sun.jndi.ldap.LdapCtx.connect(LdapCtx.java:2703)
at com.sun.jndi.ldap.LdapCtx.<init>(LdapCtx.java:293)
at com.sun.jndi.ldap.LdapCtxFactory.getUsingURL(LdapCtxFactory.java:175)
at com.sun.jndi.ldap.LdapCtxFactory.getUsingURLs(LdapCtxFactory.java:193)
at com.sun.jndi.ldap.LdapCtxFactory.getLdapCtxInstance(LdapCtxFactory.java:136)
at com.sun.jndi.ldap.LdapCtxFactory.getInitialContext(LdapCtxFactory.java:66)
at javax.naming.spi.NamingManager.getInitialContext(NamingManager.java:667)
at javax.naming.InitialContext.getDefaultInitCtx(InitialContext.java:288)
at javax.naming.InitialContext.init(InitialContext.java:223)
at javax.naming.ldap.InitialLdapContext.<init>(InitialLdapContext.java:134)
at org.springframework.ldap.core.support.LdapContextSource.getDirContextInstance(LdapContextSource.java:43)
at org.springframework.ldap.core.support.AbstractContextSource.createContext(AbstractContextSource.java:254)

如果有人能指出我的错误所在,我会感激的。此时,我只想使用LDAP对输入的用户/密码进行身份验证,没有什么比这更复杂的了。

我还对一些一般性的观点感兴趣,因为这是我第一次进入LDAP世界。

LDAP区分大小写吗?
空间最好避免吗?
避免在LDAP查询中以明文形式发送密码的一般用例/最佳实践是什么?

2 回复 | 直到 8 年前

Mike Q 14 年前

  <bean id="contextSource"
        class="org.springframework.security.ldap.DefaultSpringSecurityContextSource">
    <constructor-arg value="ldap://localhost:389/cn=Sandbox,dc=ITOrg"/>
    <property name="userDn" value="cn=superuser,cn=People,cn=Sandbox,dc=ITOrg"/>
    <property name="password" value="xxxxxx"/>
  </bean>

  <bean id="ldapAuthProvider"
        class="org.springframework.security.ldap.authentication.LdapAuthenticationProvider">
    <constructor-arg>
      <bean class="org.springframework.security.ldap.authentication.BindAuthenticator">
        <constructor-arg ref="contextSource"/>
        <property name="userDnPatterns">
          <list>
            <value>cn={0},cn=People</value>
          </list>
        </property>
      </bean>
    </constructor-arg>
  </bean>

  <bean id="userSearch" class="org.springframework.security.ldap.search.FilterBasedLdapUserSearch">
    <constructor-arg index="0" value="cn=People"/>
    <constructor-arg index="1" value="(cn={0})"/>
    <constructor-arg index="2" ref="contextSource"/>
  </bean>

<property name="userDn" value="cn=superuser,cn=People,cn=Sandbox,dc=ITOrg"/>

<value>cn={0},cn=People</value>

    <constructor-arg index="0" value="cn=People"/>
    <constructor-arg index="1" value="(cn={0})"/>

cn=People (uid={0})

    @Autowired
    private LdapUserSearch ldapUserSearch;

    @Autowired
    private AuthenticationProvider authenticationProvider;

    public void initialise()
    {
        DirContextOperations dirContextOperations = ldapUserSearch.searchForUser( "username" );

        Authentication authentication = authenticationProvider.authenticate( new UsernamePasswordAuthenticationToken( "username", "password" ) );    
    }

Error 52b - Invalid password


[LDAP: error code 32 - 0000208D: NameErr: DSID-031521D2, problem 2001 (NO_OBJECT), data 0, best match of: 'CN=Sandbox,DC=ITOrg'
     - This means the user is not in the administrator role (probably)

Hesham Masoud 11 年前