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为什么会出现错误“此服务需要API密钥”?

google-places php

0

zac · 技术社区 · 6 年前

我试图用下面的php代码向google places api发送post请求,但是我得到了一个错误

字符串(141)“{”错误消息“:”此服务需要API密钥。“, “HTML属性”:[],“结果”:[],“状态”:“请求被拒绝” }

<?php
include_once 'configuration.php';

$url = 'https://maps.googleapis.com/maps/api/place/textsearch/json';
$data = array('query' => 'restaurants in Sydney', 'key' => API_KEY);

$options = array(
    'http' => array(
        'header'  => "Content-type: application/x-www-form-urlencoded\r\n",
        'method'  => 'POST',
        'content' => http_build_query($data)
    )
);
$context  = stream_context_create($options);
$result = file_get_contents($url, false, $context);
if ($result === FALSE) { /* Handle error */ }

var_dump($result);

问题在哪里?

1 回复 | 直到 6 年前

1

2

ariefbayu 6 年前

如中所述 documentation of text search ,参数需要在get方法中。你是邮递的。

A Text Search request is an HTTP URL of the following form:

    https://maps.googleapis.com/maps/api/place/textsearch/output?parameters

...

Certain parameters are required to initiate a search request. As is standard in URLs, all parameters are separated using the ampersand (&) character.

请改为尝试此代码段:

<?php
include_once 'configuration.php';

$url = 'https://maps.googleapis.com/maps/api/place/textsearch/json?query=' . urlencode('restaurants in Sydney') . '&key=' . API_KEY;

$result = file_get_contents($url);
if ($result === FALSE) { /* Handle error */ }

var_dump($result);

要使用数组参数,请更改 $url 到:

$data = array('query' => 'restaurants in Sydney', 'key' => API_KEY);
$url = 'https://maps.googleapis.com/maps/api/place/textsearch/json?' . http_build_query($data);