丢弃所有不是实际字母的字符。使用awk-Bash

因此,我有一个脚本来寻找我的服务 vmxd.service 加载 , 跑步 忙碌的 ...

systemctl --all --type service | awk -v pat="$SERVICE" '$0 ~ pat {print $0}'

● vmxd.service                                          loaded    failed   failed  Juniper vMX Router

$SERVICE="vmxd.service"

当我在另一台主机上检查脚本时,现在不再打印 vmxd。服务 因为它是字符串上的第一个字符,所以现在正在打印[],完全破坏了我的脚本。

Here is an Output of my Script showing the [●]
[...] 
The service file: vmxd.service has been found under /etc/systemd/system/
Check if WorkingDirectory path is correct............................[OK]
Check if service exist...............................................[Found]
Check if ● is loaded...............................................[No]
Check if ● is active...............................................[No]
Enabling service....................................................../init.sh: line 189: command not found
Reloading Service....................................................[No]
Check if 'vmxd.service' has started successfully.....................[Started]

通常,我的脚本工作的服务器上的输出如下所示:

  vmxd.service                                          loaded    active   exited  Juniper vMX Router

注意:我不太清楚这个点实际上意味着什么,但不管怎样,我只需要忽略运行命令的变量中的那个字符