您可以使用
JavaScriptSerializer
类,它是
System.Web.Script
命名空间。
例如:
var jsonString = @"{""name"":""John Doe"",""age"":20}";
var JSONObj = new JavaScriptSerializer().Deserialize<Dictionary<string, string>>(jsonString );
然后
JSONObj["name"]
; 给你
"John Doe"
在这种情况下,您可以使用它:
public class Creator
{
public int Id { get; set; }
public string Name { get; set; }
public string CreatorType { get; set; }
public int CreatorTargetId { get; set; }
}
public class RootObject
{
public int TargetId { get; set; }
public object ProductType { get; set; }
public int AssetId { get; set; }
public int ProductId { get; set; }
public string Name { get; set; }
public string Description { get; set; }
public int AssetTypeId { get; set; }
public Creator Creator { get; set; }
public int IconImageAssetId { get; set; }
public DateTime Created { get; set; }
public DateTime Updated { get; set; }
public object PriceInRobux { get; set; }
public object PriceInTickets { get; set; }
public int Sales { get; set; }
public bool IsNew { get; set; }
public bool IsForSale { get; set; }
public bool IsPublicDomain { get; set; }
public bool IsLimited { get; set; }
public bool IsLimitedUnique { get; set; }
public object Remaining { get; set; }
public int MinimumMembershipLevel { get; set; }
public int ContentRatingTypeId { get; set; }
}
使用Newtonsoft。Json
var jsonString = @"{""TargetId"":0,""ProductType"":null,""AssetId"":1239281845,""ProductId"":0,""Name"":""â¤ï¸ðððððâï¸ðâ¤ï¸ Red&Black Flannel + Backpack"",""Description"":""Shirt Image"",""AssetTypeId"":1,""Creator"":{""Id"":124026176,""Name"":""TheDestroyerPeter"",""CreatorType"":""User"",""CreatorTargetId"":124026176},""IconImageAssetId"":0,""Created"":""2017-12-12T19:48:24.693Z"",""Updated"":""2017-12-12T19:48:24.693Z"",""PriceInRobux"":null,""PriceInTickets"":null,""Sales"":0,""IsNew"":false,""IsForSale"":false,""IsPublicDomain"":false,""IsLimited"":false,""IsLimitedUnique"":false,""Remaining"":null,""MinimumMembershipLevel"":0,""ContentRatingTypeId"":0}";
var obj = JsonConvert.DeserializeObject<RootObject>(jsonString);
Console.WriteLine(obj.Creator.Name);