寻找游戏策略

我想匹配如果一个元组返回提供的值,结果应该是坦白或不坦白。我们称之为回报吧。但是在下面的测试代码中,它返回(0,0)作为招供,而不是在原始列表中返回招供。

Dont confess: (-1, -1) 
Confess : (-10, 0)
Confess : (0, -10)
Dont Confess: (-10, -10)


dntCon=(-1, -1) 
conf=(-10, 0)
confess=(0, -10)
DntConff=(-5, -5)

import random 
from random import shuffle
from random import sample


x = [-1, -10, 0, -5]
y = [-1, 0, -10, -5]

#print(sample(list, len(list)))

for m in range(0, 3): 
    x=random.sample(x, len(x))
    y=random.sample(y, len(y))
    #print(x, y)

    for i in x:
        #print(i)
        for j in y:
            #print(i, j)
            if(i ==-1 & j==-1 ):
                print(i, j, "ncoo")
                #print( i, j,'')
            elif (i==-10 & j==0): 
                print(i, j, 'Confess')
            elif (i==0 & j==-10):
                print(i, j, 'Confess')
            elif (i==-10 & j==-10):
                print(i, j, 'ncoo')
            else:
                "not met"

结果

(0, 0, 'Confess')
    (-10, -10, 'ncoo')
    (-10, -1, 'ncoo')
    (-1, -1, 'ncoo')
    (0, 0, 'Confess')
    (-10, -10, 'ncoo')
    (-10, -1, 'ncoo')
    (-1, -1, 'ncoo')
    (-10, -1, 'ncoo')
    (-10, -10, 'ncoo')
    (-1, -1, 'ncoo')
    (0, 0, 'Confess')

为什么这个循环会返回( 0, 0