如何使用表中每行的2个元素(按类)调用函数?

怎么样:

var computerID = $("#ComputerID").text();

$('#gridComputerApps').children('tr').each(function() {
  var appName = $(this).find(".AppName").text();
  var licenseOutput = $(this).find(".licenseOutput").text();

  // do something with them
  yourFunc(computerID, appName, licenseOutput);
});

这样行吗?

使用jQuery遍历DOM有许多不同的方法。我建议尽可能具体地与您的选择者联系,从那里开始工作。以下是一些让你思考的想法

$('#gridComputerApps').children('tr').each(function() {  
    var $tr = $(this);

    // all td elements in the row.
    $tr.children('td'); 

    // you could use position to get the first td
    // this is the tr element in this case(!)
    var tdFirst = $('td:first', this);

    // you could get the next td like so
    // nextAll() will get the next td, next() will only get the next sibling
    tdFirst.nextAll('td');

    // get the 3rd td element.
    $tr.children('td').get(2); 

    // get the 3rd td element as a jQuery object
    $tr.children('td').eq(2);

});

$("#gridComputerApps").children("tr").each(function(){
    $(this).children(".licenseOutput").each(function(){
        // do stuff with licenseOutput 
    });
    $(this).children(".AppName").each(function(){
        // do stuff with AppName
    });
});

$("#gridComputerApps").children("td").each(function(){
    // do stuff with each cell
});

这就是你想要的吗?

试试这个怎么样?我知道它有效,因为我测试过它:

var cID = $('#ComputerID').text();

$("#gridComputerApps").find("tr").each(function(){
 var license = $(this).find(".licenseOutput");
 var appname = $(this).find(".AppName");

 for (i=0;i<license.length;i++){
  yourFunction ( cID, $(license[i]).text(), $(appname[i]).text() );
 }
});