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如何提取特定模式后出现的字符串?[关闭]

python-3.x regex python

-1

Sociopath · 技术社区 · 6 年前

str1 = "Information name: Wen Moyes address: Mcity."
str2 = "resume Name : Sam Win Father's name: Dean address"
str3 = "Father's name: Dan. Acknowledge"
str4 = "Father's Name: Joe Cena Name :- John Cena"

我想从名字后面的每个字符串中提取名字。如果字符串包含 Father's name 它应该忽略这一部分,只寻找 name

我的预期产出是

Wen Moyes
Sam Win
None
John Cena

我试过的 :

regex

re.findall(r'name\s*:(\s*\w*\s\w*)', str1.lower())

输出如下:

[' wen moyes']
[' sam win', ' dean address']
[' dan']
[' joe cena']

我该怎么办?
有没有不使用regex的替代方法?

1 回复 | 直到 6 年前

CertainPerformance 6 年前

一种选择是消极地寻找 Father's ,然后匹配 Name: (\w+ \w+) :

str1 = "Information name: Wen Moyes address: Mcity."
str2 = "resume Name : Sam Win Father's name: Dean address"
str3 = "Father's name: Dan. Acknowledge"
str4 = "Father's Name: Joe Cena Name :- John Cena"

pattern = re.compile(r"(?<!Father's )[Nn]ame ?:-? (\w+ \w+)")
for str in [str1, str2, str3, str4]:
    print(re.findall(pattern, str))

https://regex101.com/r/Gp5PDr/1