我们可以使用
str_sub
,并仅返回州缩写不匹配的行。
library(tidyverse)
df %>%
filter(str_sub(countyname, start= -2) != (str_sub(neighborname, start= -2)))
输出
countyname fipscounty neighborname fipsneighbor
1 Archuleta County, CO 8007 Rio Arriba County, NM 35039
2 Archuleta County, CO 8007 San Juan County, NM 35045
或者在base R中,我们可以使用
sub
,然后过滤数据帧。
df[sub('.*(?=.{2}$)', '', df$countyname, perl=T) !=
sub('.*(?=.{2}$)', '', df$neighborname, perl=T),]
或者使用
substr
(尽管要详细得多):
df[substr(df$countyname, nchar(df$countyname)-1, nchar(df$countyname)) !=
substr(df$neighborname, nchar(df$neighborname)-1, nchar(df$neighborname)),]
数据
df <- structure(list(countyname = c("Archuleta County, CO", "Archuleta County, CO",
"Archuleta County, CO"), fipscounty = c(8007L, 8007L, 8007L),
neighborname = c("Rio Grande County, CO", "Rio Arriba County, NM",
"San Juan County, NM"), fipsneighbor = c(8105L, 35039L, 35045L
)), class = "data.frame", row.names = c(NA, -3L))