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写一个列表,然后将其反向返回[关闭]

python

-1

user3042850 · 技术社区 · 6 年前

写一个5个数字的列表,然后再写一个数值颠倒的列表…

解决方案1有效。解决方案2,没那么多。

counter = 0
count2 = 0
list = []
otherlist = []

import random

#Solution 1
list = random.sample(range(1, 100), 5)
otherlist = list.reverse    

#Solution 2
while counter<5:
    list.append(random.randint(5,10))
    print(list[counter])
    counter = counter + 1

counter = counter - 1

while counter > (-1):
    templist.append(list[counter])
    print(list[counter])
    print("Real",templist[count2])
    counter = counter - 1
    count2 = count2 + 1

1 回复 | 直到 6 年前

Waket Zheng 6 年前

如果要反转列表,请执行以下操作:

# Solution 1
alist = random.sample(range(1, 100), 5)
otherlist = list(reversed(alist))

# Solution 2 (My favourite)
otherlist = alist[::-1]

# Solution 3
otherlist = alist[:]
otherlist.reverse()

# Solution 4
otherlist = []
for i in range(len(alist)-1, -1, -1):
    otherlist.append(alist[i])

# Solution 5
counter = count2 = 0
alist, templist = [], []
while counter<5:
    alist.append(random.randint(5,10))
    print(alist[counter])
    counter += 1

while counter > 0:
    counter -= 1
    templist.append(alist[counter])
    print(alist[counter])
    print("Real",templist[count2])    
    count2 += 1

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