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reactjs-解决setState异步问题

reactjs javascript

JChao · 技术社区 · 6 年前

我读过这篇文章: React setState not Updating Immediately

并意识到setState是异步的,可能需要第二个arg作为处理新状态的函数。

class CheckBox extends Component {
    constructor() {
        super();
        this.state = {
            isChecked: false,
            checkedList: []
        };
        this.handleChecked = this.handleChecked.bind(this);
    }

    handleChecked () {
        this.setState({isChecked: !this.state.isChecked}, this.props.handler(this.props.txt));
    }

    render () {
        return (
            <div>
                <input type="checkbox" onChange={this.handleChecked} />
                {`   ${this.props.txt}`}
            </div>
            )
    }
}

正在被另一个应用程序使用

class AppList extends Component {
    constructor() {
        super();
        this.state = {
            checked: [],
            apps: []
        };
        this.handleChecked = this.handleChecked.bind(this);
        this.handleDeleteKey = this.handleDeleteKey.bind(this);
    }
    handleChecked(client_id) {
        if (!this.state.checked.includes(client_id)) {
            let new_apps = this.state.apps;
            if (new_apps.includes(client_id)) {
                new_apps = new_apps.filter(m => {
                    return (m !== client_id);
                });
            } else {
                new_apps.push(client_id);
            }
            console.log('new apps', new_apps);
            this.setState({apps: new_apps});
            // this.setState({checked: [...checked_key, client_id]});
            console.log(this.state);
        }
    }
    render () {
        const apps = this.props.apps.map((app) =>
            <CheckBox key={app.client_id} txt={app.client_id} handler={this.handleChecked}/>
        );

        return (
            <div>
                <h4>Client Key List:</h4>
                {this.props.apps.length > 0 ? <ul>{apps}</ul> : <p>No Key</p>}
            </div> 
        );
    }


}

所以每次复选框状态改变时,我都会更新 this.state.apps 在里面 AppList

当我控制台.log new_apps ,一切都相应地工作,但是 console.log(this.state)

3 回复 | 直到 6 年前

Ricardo Costa 6 年前

setState使您能够在设置状态后生成回调函数,以便获得真实状态

this.setState({stateYouWant}, () => console.log(this.state.stateYouWant))

this.setState({apps: new_apps}, () => console.log(this.state))

rooch84 6 年前

Jonas Wilms 6 年前

实际上,不应该有两个状态保持相同的东西。相反,复选框应该是无状态的,状态应该只保留在应用程序列表中,然后向下传递:

const CheckBox = ({ text, checked, onChange }) => 
        (<span><input type="checkbox" checked={checked} onChange={() => onChange(text)} />{text}</span>);
        
class AppList extends React.Component {
  constructor() {
    super();
    this.state = { 
      apps: [
        {name: "One", checked: false },
        { name: "Two", checked: false }
      ], 
    };
  }
  
  onChange(app) {
    this.setState(
      previous => ({ 
         apps: previous.apps.map(({ name, checked }) => ({ name, checked: checked !== (name === app) })),
      }),
      () => console.log(this.state)
    );
  }
  
  render() {
    return <div>
     {this.state.apps.map(({ name, checked }) => (<CheckBox text={name} checked={checked} onChange={this.onChange.bind(this)} />))}
    </div>;
  }
}

ReactDOM.render(<AppList />, document.body);

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>