UTF-8解码器在非ASCII字符上失败

我的部分库解码UTF-8编码 char 指向原始 unsigned 代码点。但是,某些平面不能正确解码。让我们看看(相关的)代码:

typedef struct string {
 unsigned long length;
 unsigned *data;
} string;

// really simple stuff

string *upush(string *s, unsigned c) {
 if (!s->length) s->data = (unsigned *) malloc((s->length = 1) * sizeof(unsigned));
 else   s->data = (unsigned *) realloc(s->data, ++s->length * sizeof(unsigned));
 s->data[s->length - 1] = c;
 return s;
}

// UTF-8 conversions

string ctou(char *old) {
 unsigned long i, byte = 0, cur = 0;
 string new;
 new.length = 0;
 for (i = 0; old[i]; i++)
  if (old[i] < 0x80) upush(&new, old[i]);
  else if (old[i] < 0xc0)
   if (!byte) {
    byte = cur = 0;
    continue;
   } else {
    cur |= (unsigned)(old[i] & 0x3f) << (6 * (--byte));
    if (!byte) upush(&new, cur), cur = 0;
   }
  else if (old[i] < 0xc2) continue;
  else if (old[i] < 0xe0) {
   cur = (unsigned)(old[i] & 0x1f) << 6;
   byte = 1;
  }
  else if (old[i] < 0xf0) {
   cur = (unsigned)(old[i] & 0xf) << 12;
   byte = 2;
  }
  else if (old[i] < 0xf5) {
   cur = (unsigned)(old[i] & 0x7) << 18;
   byte = 3;
  }
  else continue;
 return new;
}

全部 upush 顺便说一句,is把一个代码点推到 string ,根据需要重新分配内存。 ctou byte cur .

代码对我来说似乎都是正确的。让我们试着解码 U+10ffff ,即 f4 8f bf bd 在UTF-8中。这样做:

long i;
string b = ctou("\xf4\x8f\xbf\xbd");
for (i = 0; i < b.length; i++)
 printf("%z ", b.data[i]);

应打印:

10ffff

fffffff4 ffffff8f ffffffbf ffffffbd

ffffff 在它前面钉上。

我的代码有什么问题吗?