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如何更改JS中的子元素顺序?

html javascript

Kosmoé¶ · 技术社区 · 10 年前

我有这个html:

<table>
    <tr>
        <td>
            Set right order
        </td>
        <td>
            <span style = "display: block;">asd | <a href = '#' onclick = "moveChoiceTo(this, -1);">&uarr;</a><a href = '#' onclick = "moveChoiceTo(this, 1);">&darr;</a></span>
            <span style = "display: block;">dsa | <a href = '#' onclick = "moveChoiceTo(this, -1);">&uarr;</a><a href = '#' onclick = "moveChoiceTo(this, 1);">&darr;</a></span>
            <span style = "display: block;">qwe | <a href = '#' onclick = "moveChoiceTo(this, -1);">&uarr;</a><a href = '#' onclick = "moveChoiceTo(this, 1);">&darr;</a></span>
            <span style = "display: block;">ewq | <a href = '#' onclick = "moveChoiceTo(this, -1);">&uarr;</a><a href = '#' onclick = "moveChoiceTo(this, 1);">&darr;</a></span>
        </td>
    </tr>
</table>

这个JS:

function moveChoiceTo(elem_choice, direction)
{
    var curr_index = -1; //index of elem that we should move
    var td = elem_choice.parentElement.parentElement; //link to TD

    for (var i = 0; i < td.children.length; i++) //determine index of elem that called this function
        if (td.children[i].children[0] == elem_choice)
        {
            curr_index = i;
            break;
        }

    if (curr_index == -1)
        return;

    if (curr_index == 0 && direction < 0) //if nowhere to move
        return;

    if (curr_index == td.children.length - 1 && direction > 0) //if nowhere to move
        return;

    var curr_child = td.children[curr_index]; //save current elem into temp var
    td.children.splice(curr_index, 1); //here I getting exception that splice isn't supported by object, but arent this is array?
    td.children.splice(curr_index + direction, 0, curr_child); //attempt to insert it
}

我有个例外 splice 不支持,但这应该是一个数组并支持此方法? 我还有什么办法改变孩子的秩序?

3 回复 | 直到 10 年前

dfsq 10 年前

我将用更简单(更好)的方法补充答案:

function moveChoiceTo(elem_choice, direction) {

    var span = elem_choice.parentNode,
        td = span.parentNode;

    if (direction === -1 && span.previousElementSibling) {
        td.insertBefore(span, span.previousElementSibling);
    } else if (direction === 1 && span.nextElementSibling) {
        td.insertBefore(span, span.nextElementSibling.nextElementSibling)
    }
}

关键思想是使用 insertBefore 方法正确。您也不需要从DOM中删除任何内容。

演示: http://jsfiddle.net/dq8a0ttt/

Aleksandar Gajic 10 年前

HTMLCollection中不支持拼接,您需要使用.removeChild和.insert

var before = td.children[curr_index + direction];
var child = td.children[curr_index];

td.removeChild(child);
td.insertBefore(child, before); //attempt to insert it

Atomenergy 3 年前

等同于 dfsq的 但有一些修改。

var selected_element;


function moveElementTo(selected_element, direction) {

    var element_to_move = selected_element,
        td = element_to_move.parentNode;

    if (direction === -1 && element_to_move.previousElementSibling) {
        td.insertBefore(element_to_move, element_to_move.previousElementSibling);
    } else if (direction === 1 && element_to_move.nextElementSibling) {
        td.insertBefore(element_to_move, element_to_move.nextElementSibling.nextElementSibling)
    }
}



function move(dir){
    if (selected_element != undefined){
        moveElementTo(selected_element,dir);
    }else{
        console.error("No element Selected to move!");
    }

}

<div >

    <div onclick='selected_element = this;'><button onclick='selected_element = this.parentNode;'> Select element </button>Element One <button onclick='move(-1);'>Move_up</button></div>
    <div onclick='selected_element = this;'><button onclick='selected_element = this.parentNode;'> Select element </button>Element Two <button onclick='move(-1);'>Move_up</button></div>
    <div onclick='selected_element = this;'><button onclick='selected_element = this.parentNode;'> Select element </button>Element Three <button onclick='move(-1);'>Move_up</button></div>


</div>

我的场景是需要首先选择一个元素,因为我将它用于一个弹出式对话框,在该对话框中,长按就会显示操作,选择元素按钮只是为了演示。