检查两个浮动是否在给定的范围列表中的任何一个范围内

如果你只是想得到一个 True 或 False 因此,请考虑以下几点。

>>> a = 0.4
>>> b = 0.6
>>> 
>>> ranges = [[0,0.33], [0.33,0.66], [0.66,1.0]]
>>> 
>>> any(low <= a <= high and low <= b <= high for low, high in ranges)
True

如果您有任意数量的数字要检查(不仅仅是 a 和 b

>>> numbers = [0.4, 0.6, 0.34]
>>> any(all(low <= x <= high for x in numbers) for low, high in ranges)
True

这样地:

RANGES = [[0,0.33], [0.33,0.66], [0.66,1.0]]


def check(no_a, no_b):
    for rng in RANGES:
        if rng[0] < no_a < rng[1] and rng[0] < no_b < rng[1]:
            return True
    else:
        return False


print(check(.1, .2))
print(check(.1, .4))

True
False

或者像这样:

no_a, no_b = .1, .2
print(any(rng[0] < no_a < rng[1] and rng[0] < no_b < rng[1] for rng in RANGES))
no_a, no_b = .1, .4
print(any(rng[0] < no_a < rng[1] and rng[0] < no_b < rng[1] for rng in RANGES))

输出为:

看一看 here

把你的 no_a 和 no_b 并检查是否所有事件都通过了您的语句。

第二次编辑: all 对于这个小数据集,函数的性能优于numpy版本,因此取消了numpy的使用:

ranges = [[0,0.33], [0.33,0.66], [0.66,1.0]]

for i in range(len(ranges)):
    if all([ranges[i][0] < no_a < ranges[i][1], 
            ranges[i][0] < no_b < ranges[i][1]]):
        print('Both values are in the interval of %s' %ranges[i])

Numpy使用广播

import numpy as np

check = np.array([[0.4], [0.6]])
ranges = np.array([[0,0.33], [0.33,0.66], [0.66,1.0]])

((check >= ranges[:, 0]) & (check <= ranges[:, 1])).all(0).any()

True

细节

check >= ranges[:, 0]

#  0.00  0.33  0.66     <
[[ True  True False]  # 0.4
 [ True  True False]] # 0.6

check <= ranges[:, 1]

#  0.33  0.66  1.00      >     
[[False  True  True]   # 0.4
 [False  True  True]]  # 0.6

a = (check >= ranges[:, 0]) & (check <= ranges[:, 1])
a

#  0.00  0.33  0.66      <
#  0.33  0.66  1.00      >     
[[False  True False]   # 0.4
 [False  True False]]  # 0.6

check 要在一个范围对中,一列的所有内容都必须是 True

a.all(0)

[False  True False]

只要有一个是 是的

a.all(0).any()

True

纽皮雷杜

然而,我们本可以改变 检查 ranges 进行一次比较操作。

b = [1, -1]
(check.T * b >= ranges * b).all(1).any()

True