Pull id(整数)转换为字符串Laravel

尝试此代码

$alphabets = new Alphabet();
return $alphabets->all()->pluck('name', 'id');

Alphabet.php

你应该这样投稿。

  protected $casts = [
    'id' => 'integer',
    'name' => 'string' 
  ];

https://laracasts.com/discuss/channels/laravel/pluck-id-integer-cast-to-string

在这里,我发现JSON只允许键名是字符串。

Using number as "index" (JSON)

{
    "1": "Apple",
    "2": "Ball",
    "3": "Cat"
}

实际上,我想实现它 Form Collective 这是一个错误,它的公关现在已经合并。

https://github.com/LaravelCollective/html/pull/368#pullrequestreview-46820423

 $alphabets = new Alphabet();
    $alphaArr =$alphabets->pluck('name', 'id');
    foreach($array as $key => $value) {
       $newArray[(int) $key] = $value;
    }

pluck() 在字符串值中。

select 这样的陈述:

$data = Alphabet::select('id','name')->get()->toArray();

array:3 [▼
  0 => array:2 [▼
    "id" => 1
    "name" => "Apple"
  ]
  1 => array:2 [▼
    "id" => 2
    "name" => "Ball"
  ]
  2 => array:2 [▼
    "id" => 3
    "name" => "Cat"
  ]
]

$expected = array();

foreach($data as $d){
    $expected[$d['name']] = $d['id'];
}

dd($expected);

添加此行修复了LaravelCollective/Html的旧会话问题。

|| in_array((string) $value, $selected, true)

/**
 * Determine if the value is selected.
 *
 * @param  string $value
 * @param  string $selected
 *
 * @return null|string
 */
protected function getSelectedValue($value, $selected)
{
    if (is_array($selected)) {
        return in_array($value, $selected, true) || in_array((string) $value, $selected, true) ? 'selected' : null;
    } elseif ($selected instanceof Collection) {
        return $selected->contains($value) ? 'selected' : null;
    }
    return ((string) $value == (string) $selected) ? 'selected' : null;
}