我有一个矩阵
2x4x3x3
,其中2表示两个矩阵的组合
A1
和
A2
是的。对于每个矩阵
A1/A2
(尺寸
4x3x3
),我只选择大于
0.3
(小于
0.3分
打电话
不确定位置
)表演
argmax
获得矩阵
C
是的。在矩阵c中,我将在
不确定位置
到255。我用python中的两种方法完成了它,如下所示。我正在寻找第三种更短的方法来设置
不确定位置
到255。我们能要吗?谢谢
代码是
import numpy as np
A1=np.array([[[0.4,0.2,0.3],
[0.4,0.5,0.6],
[0.7,0.8,0.2]],
[[0.4,0.5,.3],
[0.2,0.5,0.2],
[0.3,0.2,0.1]],
[[0.5,0.1,0.6],
[0.8,0.1,0.5],
[0.5,0.1,0.4]],
[[0.6,0.1,0.1],
[0.2,0.1,0.9],
[0.9,0.1,0.1]]])
A2=np.array([[[0.8,0.1,0.6],
[0.4,0.6,0.6],
[0.7,0.8,0.2]],
[[0.4,0.8,.3],
[0.2,0.8,0.2],
[0.3,0.0,0.1]],
[[0.5,0.1,0.6],
[0.8,0.0,0.5],
[0.5,0.1,0.4]],
[[0.6,0.1,0.1],
[0.2,0.1,0.1],
[0.9,0.1,0.1]]])
A1= np.expand_dims(A1,0)
A2= np.expand_dims(A2,0)
A= np.concatenate([A1,A2],axis=0)
B = A< 0.3
#First way
C=np.argmax(A, axis=1)
C[B[:,0,:,:]]=255
C[B[:,1,:,:]]=255
C[B[:,2,:,:]]=255
C[B[:,3,:,:]]=255
print (C)
#Second way
C=np.argmax(A, axis=1)
for i in range (4):
C[B[:,i,:,:]] = 255
print (C)
#Third way
C=np.argmax(A, axis=1)
C[B[:,0:3,:,:]]=255
print (C)
你也可以运行它
Online Code