在遍历最小堆时获取垃圾值

即使你在回答中发布了“修复”,你也会遇到同样的问题 heap_size >= (maxsize/2) 。您必须检查计算的左、右子索引。更正的代码:

void heapTraversal(){
    for(int i = 0; i<heap_size; i++){
        cout << "Current value is : " << hipa[i] << endl;
        int left = (2*i)+1;

        if(left < heap_size && hipa[left]){
            cout << "Left child is : " << hipa[left] << endl;
        }
        else{
            cout << "Left child does not exist" << endl;
        }

        int right = left+1;
        if(right < heap_size && hipa[right]){
            cout << "Right child is : " << hipa[right] << endl;
        }
        else{
            cout << "Right child does not exist" << endl;
        }

我已经通过将for循环参数从maxsize更改为heap\u size解决了这个问题。 maxsize应该是堆的容量,而heap\u size是堆的当前大小。我为好奇者添加了类声明的其余部分。

class minHeap{
    int *hipa;
    int maxsize;
    int heap_size;

public:
    minHeap(int size);
    void minHeapbuild(int );

    int root(int i){
        return (i-1)/2;
    }
    int left(int i){
        return (2*i+1);
    }
    int right(int i){
        return (2*i+2);
    }

    int extractRoot();
    void decreaseKey(int i, int newKey);
    void deleteKey(int key);
    void addKey(int key);

    int getRoot(){
        return hipa[0];
    }
}