代码之家 › 专栏 › 技术社区 › Nicole Foster

可变利率。当利率符合条件时,我怎样才能让它转换呢

recursion loops python-3.x python

-1

Nicole Foster · 技术社区 · 6 年前

我正试图让利率在总复合利率达到其范围时自动转换。我输入,校长,每月的总数和学期。它只计算第一年的复利。我希望它能够将这个数量发送回函数,以便它重新计算,直到术语结束。

def IntEarned(p, m, t):
    principal = p
    monthly_deposit = m
    invested = t


        currentamount = principal + (monthly_deposit * 12)

    def currentTest():

        if currentamount < 100000:
            interest =  (0.05 / 100)
            return interest
        elif currentamount < 200000:
            interest =  (0.10 / 100)
            return interest
        elif currentamount < 250000:
            interest =  (0.15 / 100)
            return interest
        elif currentamount < 500000:
            interest = (0.25 / 100)
            return interest
        elif currentamount < 1000000:
            interest = (0.40 / 100)
            return interest
        elif currentamount < 2000000:
            interest =  (0.55 / 100)
            return interest
        elif currentamount < 5000000:
            interest =  (0.60 / 100)
            return interest
        elif currentamount >= 5000000:
            interest =  (0.70 / 100)
            return interest



    while (invested > 0):
        currentamount = currentamount + (currentamount * currentTest())
        invested = invested - 1
        return currentamount

所以我用网络学习(10000,10000),得到10125.06,这是第一年的成绩。

2 回复 | 直到 6 年前

Scratch'N'Purr 6 年前

def calc_accrual(p, m, t, i):
    t -= 1
    p = p + (m * 12)

    if p < 100000:
        i += p * 0.0005
        p *= 1.0005
    elif p < 200000:
        i += p * 0.0010
        p *= 1.0010
    elif p < 250000:
        i += p * 0.0015
        p *= 1.0015
    elif p < 500000:
        i += p * 0.0025
        p *= 1.0025
    elif p < 1000000:
        i += p * 0.0040
        p *= 1.0040
    elif p < 2000000:
        i += p * 0.0055
        p *= 1.0055
    elif p < 5000000:
        i += p * 0.0060
        p *= 1.0060
    else:
        i += p * 0.0070
        p *= 1.0070

    if t > 0:
        return calc_accrual(p, m, t, i)
    else:
        return p, i

测验 :

>>> calc_accrual(10000, 10, 1, 0)
>>> (10125.06, 5.0600000000000005)
>>> calc_accrual(10000, 10, 1000, 0)
>>> (204357.25738374083, 74357.25738374837)

Stephen Rauch Afsar Ali 6 年前

您可以通过以下搜索将您的范围转换为利率:

def interest_per_value(value):
    interest_table = (
        (100000, 0.05),
        (200000, 0.10),
        (250000, 0.15),
        (500000, 0.25),
        (1000000, 0.40),
        (2000000, 0.55),
        (5000000, 0.60),
    )
    for test_value, rate in interest_table:
        if value < test_value:
            return rate / 100
        return 0.70 / 100